What is the foci 25x^2+64y^2=1600 ?

The foci 25x^2+64y^2=1600 is (sqrt(39),0),(-sqrt(39),0)

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foci 25x^2+64y^2=1600

foci

25 x^{2} + 64 y^{2} = 1600

(39, 0), (- 39, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

25 x^{2} + 64 y^{2} = 1600 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} - 5^{2} : 39

(0 + 39, 0), (0 - 39, 0)

Refine

(39, 0), (- 39, 0)

\frac{( x + 2 ) ^{2}}{22} + \frac{( y + 3 ) ^{2}}{18} = 1

25 (x + 2)^{2} + 4 (y - 3)^{2} = 100

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

16 x^{2} + 25 y^{2} - 224 x + 250 y = 191

\frac{( x - 1 ) ^{2}}{40} + \frac{( y + 4 ) ^{2}}{36} = 1

What is the foci 25x^2+64y^2=1600 ?
The foci 25x^2+64y^2=1600 is (sqrt(39),0),(-sqrt(39),0)