What is the foci (x^2)/(36)+(y^2)/(121)=1 ?

The foci (x^2)/(36)+(y^2)/(121)=1 is (0,sqrt(85)),(0,-sqrt(85))

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foci (x^2)/(36)+(y^2)/(121)=1

foci

\frac{x ^{2}}{36} + \frac{y ^{2}}{121} = 1

(0, 85), (0, - 85)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{36} + \frac{y ^{2}}{121} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 11, a = 6

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 1^{2} - 6^{2} : 85

(0, 0 + 85), (0, 0 - 85)

Refine

(0, 85), (0, - 85)

2 x^{2} + y^{2} + 12 x - 2 y + 11 = 0

16 x^{2} + 9 y^{2} + 64 x - 80 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

16 x^{2} + 4 y^{2} + 96 x - 24 y + 116 = 0

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

What is the foci (x^2)/(36)+(y^2)/(121)=1 ?
The foci (x^2)/(36)+(y^2)/(121)=1 is (0,sqrt(85)),(0,-sqrt(85))