What is the foci ((x^2))/(16)+((y^2))/(36)=1 ?

The foci ((x^2))/(16)+((y^2))/(36)=1 is (0,2sqrt(5)),(0,-2sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((x^2))/(16)+((y^2))/(36)=1

foci

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{36} = 1

(0, 25), (0, - 25)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 6, a = 4

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} - 4^{2} : 25

(0, 0 + 25), (0, 0 - 25)

Refine

(0, 25), (0, - 25)

x^{2} + 4 y^{2} + 10 x + 8 y - 3 = 0

36 x^{2} + y^{2} = 36

\frac{( x + 1 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{25} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

4 x^{2} + y^{2} - 8 x + 4 y - 8 = 0

What is the foci ((x^2))/(16)+((y^2))/(36)=1 ?
The foci ((x^2))/(16)+((y^2))/(36)=1 is (0,2sqrt(5)),(0,-2sqrt(5))