What is the center (x^2)/(100)+(y^2)/(36)=1 ?

The center (x^2)/(100)+(y^2)/(36)=1 is (0,0)

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center (x^2)/(100)+(y^2)/(36)=1

center

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 6

And the center is:

(0, 0)

3 x^{2} + y^{2} - 24 x + 39 = 0

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{25} = 1

64 x^{2} + 100 y^{2} + 768 x - 600 y - 3196 = 0

2 x^{2} + 3 y^{2} - 4 x + 6 y - 1 = 0

x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

What is the center (x^2)/(100)+(y^2)/(36)=1 ?
The center (x^2)/(100)+(y^2)/(36)=1 is (0,0)