What is the center (x^2)/(63500)+(y^2)/(50900)=1 ?

The center (x^2)/(63500)+(y^2)/(50900)=1 is (0,0)

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center (x^2)/(63500)+(y^2)/(50900)=1

center

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

Rewrite

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 10 635 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 10 509 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10635, b = 10509

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10635, b = 10509

And the center is:

(0, 0)

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

x^{2} + \frac{y ^{2}}{16} = 1

25 x^{2} - 200 x + y^{2} + 4 y + 379 = 0

4 x^{2} + 9 y^{2} - 24 x + 72 y + 144 = 0

4 x^{2} + y^{2} + 8 x - 4 y + 4 = 0

What is the center (x^2)/(63500)+(y^2)/(50900)=1 ?
The center (x^2)/(63500)+(y^2)/(50900)=1 is (0,0)