What is the center x^2+9y^2+6x-90y+225=0 ?

The center x^2+9y^2+6x-90y+225=0 is (-3,5)

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center x^2+9y^2+6x-90y+225=0

center

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0

(- 3, 5)

Solution steps

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0

Rewrite

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{3 ^{2}} + \frac{( y - 5 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, 5), a = 3, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 3, 5), a = 3, b = 1

And the center is:

(- 3, 5)

13 x^{2} + 49 y^{2} = 637

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

x^{2} + 4 y^{2} - 6 x - 16 y + 21 = 0

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

36 x^{2} + 25 y^{2} = 900

What is the center x^2+9y^2+6x-90y+225=0 ?
The center x^2+9y^2+6x-90y+225=0 is (-3,5)