What is the center x^2-4x+9y^2+54y+4=0 ?

The center x^2-4x+9y^2+54y+4=0 is (2,-3)

Popular >

center x^2-4x+9y^2+54y+4=0

center

x^{2} - 4 x + 9 y^{2} + 54 y + 4 = 0

(2, - 3)

Solution steps

x^{2} - 4 x + 9 y^{2} + 54 y + 4 = 0

Rewrite

x^{2} - 4 x + 9 y^{2} + 54 y + 4 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{9 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 3), a = 9, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, - 3), a = 9, b = 3

And the center is:

(2, - 3)

\frac{( x - 4 ) ^{2}}{100} + \frac{( y + 5 ) ^{2}}{64} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{52} = 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

2 x^{2} - 12 x + y^{2} + 6 y + 26 = 0

9 x^{2} + 25 y^{2} + 36 x + 150 y + 36 = 0

What is the center x^2-4x+9y^2+54y+4=0 ?
The center x^2-4x+9y^2+54y+4=0 is (2,-3)