What is the center 4x^2+9y^2=25 ?

The center 4x^2+9y^2=25 is (0,0)

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center 4x^2+9y^2=25

center

4 x^{2} + 9 y^{2} = 25

(0, 0)

Solution steps

4 x^{2} + 9 y^{2} = 25

Rewrite

4 x^{2} + 9 y^{2} = 25

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{5}{3} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{5}{2}, b = \frac{5}{3}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{5}{2}, b = \frac{5}{3}

And the center is:

(0, 0)

3 x^{(2)} + 2 y^{(2)} - 12 x + 8 y + 19 = 0

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

3 x^{2} + y^{2} + 2 x - 6 y = 3

x^{2} + \frac{( y + 2 ) ^{2}}{4} = 1

x^{2} + 9 y^{2} - 14 x + 36 y + 49 = 0