What is the eccentricity (x^2)/(100)+(y^2)/(64)=1 ?

The eccentricity (x^2)/(100)+(y^2)/(64)=1 is 3/5

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eccentricity (x^2)/(100)+(y^2)/(64)=1

eccentricity

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

\frac{3}{5}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 8

= \frac{1 0 ^{2} - 8 ^{2}}{10}

\frac{1 0 ^{2} - 8 ^{2}}{10} = \frac{3}{5}

= \frac{3}{5}

9 x^{2} + 25 y^{2} - 36 x - 50 y + 60 = 0

81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

3 x^{2} + y^{2} - 24 x + 39 = 0

9 x^{2} + 16 y^{2} = 144

4 x^{2} + y^{2} + 8 x - 4 y + 4 = 0

What is the eccentricity (x^2)/(100)+(y^2)/(64)=1 ?
The eccentricity (x^2)/(100)+(y^2)/(64)=1 is 3/5