What is the eccentricity (x^2}{16}+\frac{y^2)/9 =1 ?

The eccentricity (x^2}{16}+\frac{y^2)/9 =1 is (sqrt(7))/4

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eccentricity (x^2}{16}+\frac{y^2)/9 =1

eccentricity

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

\frac{7}{4}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 3

= \frac{4 ^{2} - 3 ^{2}}{4}

\frac{4 ^{2} - 3 ^{2}}{4} = \frac{7}{4}

= \frac{7}{4}

14 x^{2} + 9 y^{2} = 126

10 x^{2} + 3 y^{2} = 30

\frac{y ^{2}}{64} + \frac{x ^{2}}{36} = 1

3 x^{2} + y^{2} + 2 x - 6 y = 3

3 x^{2} + 12 x + 4 y^{2} - 40 y + 100 = 0

What is the eccentricity (x^2}{16}+\frac{y^2)/9 =1 ?
The eccentricity (x^2}{16}+\frac{y^2)/9 =1 is (sqrt(7))/4