What is -f(x)=3(x)^2+4(x)-3 ?

The solution to -f(x)=3(x)^2+4(x)-3 is Parabola with (h,k)=(-2/3 , 13/3),p=-1/12

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-f(x)=3(x)^2+4(x)-3

- f (x) = 3 (x)^{2} + 4 (x) - 3

(h, k) = (- \frac{2}{3}, \frac{13}{3}), p = - \frac{1}{12}

Solution steps

- y = 3 x^{2} + 4 x - 3

Rewrite

- y = 3 x^{2} + 4 x - 3

in the standard form

4 (- \frac{1}{12}) (y - \frac{13}{3}) = (x - (- \frac{2}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{2}{3}, \frac{13}{3}), p = - \frac{1}{12}

x^{2} + 6 x - 16 y + 135 = 0

(x - 5)^{2} = 12 (y + 3)

x + 4 - y^{2} = 0

- 2 x^{2} - 2 y = - 6

y^{2} - 4 x - 8 y - 12 = 0

What is -f(x)=3(x)^2+4(x)-3 ?
The solution to -f(x)=3(x)^2+4(x)-3 is Parabola with (h,k)=(-2/3 , 13/3),p=-1/12