What is the eccentricity 5x^2+7y^2=70 ?

The eccentricity 5x^2+7y^2=70 is sqrt(2/7)

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eccentricity 5x^2+7y^2=70

eccentricity

5 x^{2} + 7 y^{2} = 70

\frac{2}{7}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

5 x^{2} + 7 y^{2} = 70 :

Ellipse with center

(h, k) = (0, 0), a = 14, b = 10

= \frac{( 14 ) ^{2} - ( 10 ) ^{2}}{14}

\frac{( 14 ) ^{2} - ( 10 ) ^{2}}{14} = \frac{2}{7}

= \frac{2}{7}

5 x^{2} + 10 y^{2} = 50

x^{2} + 4 y^{2} - 2 x - 16 y + 13 = 0

x^{2} = 4 y - 2 y^{2}

\frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

25 x^{2} + 9 y^{2} - 100 x + 18 y - 116 = 0

What is the eccentricity 5x^2+7y^2=70 ?
The eccentricity 5x^2+7y^2=70 is sqrt(2/7)