What is the eccentricity (x^2)/8+(y^2)/3 =1 ?

The eccentricity (x^2)/8+(y^2)/3 =1 is (sqrt(5))/(2sqrt(2))

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eccentricity (x^2)/8+(y^2)/3 =1

eccentricity

\frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1

\frac{5}{2 2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 22, b = 3

= \frac{( 2 2 ) ^{2} - ( 3 ) ^{2}}{2 2}

\frac{( 2 2 ) ^{2} - ( 3 ) ^{2}}{2 2} = \frac{5}{2 2}

= \frac{5}{2 2}

10 x^{2} + 5 y^{2} = 50

9 x^{2} + 16 y^{2} - 144 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

4 x^{2} + 3 y^{2} - 8 x + 18 y + 19 = 0

What is the eccentricity (x^2)/8+(y^2)/3 =1 ?
The eccentricity (x^2)/8+(y^2)/3 =1 is (sqrt(5))/(2sqrt(2))