What is the eccentricity (x^2)/(16)+(y^2)/(80)=1 ?

The eccentricity (x^2)/(16)+(y^2)/(80)=1 is 2/(sqrt(5))

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eccentricity (x^2)/(16)+(y^2)/(80)=1

eccentricity

\frac{x ^{2}}{16} + \frac{y ^{2}}{80} = 1

\frac{2}{5}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{80} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 45, a = 4

= \frac{( 4 5 ) ^{2} - 4 ^{2}}{4 5}

\frac{( 4 5 ) ^{2} - 4 ^{2}}{4 5} = \frac{2}{5}

= \frac{2}{5}

2 x^{2} + y^{2} = 50

4 x^{2} + 3 y^{2} + 8 x - 24 y + 51 = 0

x^{2} + y^{2} + 6 x - 4 y - 3 = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

4 x^{2} + y^{2} = 16

What is the eccentricity (x^2)/(16)+(y^2)/(80)=1 ?
The eccentricity (x^2)/(16)+(y^2)/(80)=1 is 2/(sqrt(5))