What is the eccentricity (x^2)/(16)+(y^2)/(25)=1 ?

The eccentricity (x^2)/(16)+(y^2)/(25)=1 is 3/5

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eccentricity (x^2)/(16)+(y^2)/(25)=1

eccentricity

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

\frac{3}{5}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 4

= \frac{5 ^{2} - 4 ^{2}}{5}

\frac{5 ^{2} - 4 ^{2}}{5} = \frac{3}{5}

= \frac{3}{5}

18 y^{2} + 24 y + 12 x^{2} - 12 x = 1

+ 9 x^{2} + 4 y^{2} = 36

9 x^{2} + 4 y^{2} + 54 x - 8 y + 49 = 0

(\frac{x}{8})^{2} + (\frac{y}{6})^{2} = 1

4 x^{2} + 9 y^{2} - 8 x - 32 = 0

What is the eccentricity (x^2)/(16)+(y^2)/(25)=1 ?
The eccentricity (x^2)/(16)+(y^2)/(25)=1 is 3/5