What is the eccentricity 3x^2+7y^2=63 ?

The eccentricity 3x^2+7y^2=63 is 2/(sqrt(7))

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eccentricity 3x^2+7y^2=63

eccentricity

3 x^{2} + 7 y^{2} = 63

\frac{2}{7}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

3 x^{2} + 7 y^{2} = 63 :

Ellipse with center

(h, k) = (0, 0), a = 21, b = 3

= \frac{( 21 ) ^{2} - 3 ^{2}}{21}

\frac{( 21 ) ^{2} - 3 ^{2}}{21} = \frac{2}{7}

= \frac{2}{7}

\frac{x ^{2}}{160} + \frac{y ^{2}}{16} = 1

9 x^{2} + 25 y^{2} + 108 x - 200 y + 499 = 0

x^{2} + 2 y^{2} - 2 x + 8 y + 5 = 0

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1

What is the eccentricity 3x^2+7y^2=63 ?
The eccentricity 3x^2+7y^2=63 is 2/(sqrt(7))