What is the eccentricity ((x)^2)/(12)+((y)^2)/(16)=1 ?

The eccentricity ((x)^2)/(12)+((y)^2)/(16)=1 is 1/2

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eccentricity ((x)^2)/(12)+((y)^2)/(16)=1

eccentricity

\frac{( x ) ^{2}}{12} + \frac{( y ) ^{2}}{16} = 1

\frac{1}{2}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{12} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 23

= \frac{4 ^{2} - ( 2 3 ) ^{2}}{4}

\frac{4 ^{2} - ( 2 3 ) ^{2}}{4} = \frac{1}{2}

= \frac{1}{2}

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

9 x^{2} + 49 y^{2} = 441

\frac{x ^{2}}{324} + \frac{y ^{2}}{400} = 1

\frac{x ^{2}}{1} + \frac{y ^{2}}{1} = 1

4 x^{2} + 3 y^{2} + 24 x + 36 y + 72 = 0

What is the eccentricity ((x)^2)/(12)+((y)^2)/(16)=1 ?
The eccentricity ((x)^2)/(12)+((y)^2)/(16)=1 is 1/2