What is the eccentricity 4y^2+9x^2=36 ?

The eccentricity 4y^2+9x^2=36 is (sqrt(5))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

eccentricity 4y^2+9x^2=36

eccentricity

4 y^{2} + 9 x^{2} = 36

\frac{5}{3}

Decimal

0.74535 \dots

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

4 y^{2} + 9 x^{2} = 36 :

Ellipse with center

(h, k) = (0, 0), b = 3, a = 2

= \frac{3 ^{2} - 2 ^{2}}{3}

\frac{3 ^{2} - 2 ^{2}}{3} = \frac{5}{3}

= \frac{5}{3}

2 x^{2} + 3 y^{2} + 4 x = 1

25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0

18 x^{2} + 8 y^{2} + 36 x - 32 y - 22 = 0

\frac{x ^{2}}{5} + \frac{y ^{2}}{4.58} = 1

3 x^{2} + 2 y^{2} - 12 x + 8 y + 19 = 0

What is the eccentricity 4y^2+9x^2=36 ?
The eccentricity 4y^2+9x^2=36 is (sqrt(5))/3