What is the eccentricity (x^2)/(12)+(y^2)/(49)=1 ?

The eccentricity (x^2)/(12)+(y^2)/(49)=1 is (sqrt(37))/7

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eccentricity (x^2)/(12)+(y^2)/(49)=1

eccentricity

\frac{x ^{2}}{12} + \frac{y ^{2}}{49} = 1

\frac{37}{7}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{12} + \frac{y ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 7, a = 23

= \frac{7 ^{2} - ( 2 3 ) ^{2}}{7}

\frac{7 ^{2} - ( 2 3 ) ^{2}}{7} = \frac{37}{7}

= \frac{37}{7}

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

16 x^{2} + 9 y^{2} + 160 x - 72 y + 544 = 144

\frac{x ^{2}}{25} + \frac{y ^{2}}{64} = 1

x^{2} + 9 y^{2} + 16 x + 18 y + 64 = 0

What is the eccentricity (x^2)/(12)+(y^2)/(49)=1 ?
The eccentricity (x^2)/(12)+(y^2)/(49)=1 is (sqrt(37))/7