What is the eccentricity (x^2)/(13.44)+(y^2)/(16)=1 ?

The eccentricity (x^2)/(13.44)+(y^2)/(16)=1 is 0.4

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eccentricity (x^2)/(13.44)+(y^2)/(16)=1

eccentricity

0.4

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{13.44} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 13.44

= \frac{4 ^{2} - ( 13.44 ) ^{2}}{4}

\frac{4 ^{2} - ( 13.44 ) ^{2}}{4} = 0.4

= 0.4

What is the eccentricity (x^2)/(13.44)+(y^2)/(16)=1 ?
The eccentricity (x^2)/(13.44)+(y^2)/(16)=1 is 0.4