What is the eccentricity ((x-1)^2)/2+(y^2)/1 =1 ?

The eccentricity ((x-1)^2)/2+(y^2)/1 =1 is 1/(sqrt(2))

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eccentricity ((x-1)^2)/2+(y^2)/1 =1

eccentricity

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1

\frac{1}{2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1 :

Ellipse with center

(h, k) = (1, 0), a = 2, b = 1

= \frac{( 2 ) ^{2} - 1 ^{2}}{2}

\frac{( 2 ) ^{2} - 1 ^{2}}{2} = \frac{1}{2}

= \frac{1}{2}

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

\frac{( x - 3 ) ^{2}}{2} + \frac{( y - 4 ) ^{2}}{4} = 1

8 x^{2} + 4 y^{2} + 16 x - 12 y - 15 = 0

\frac{( x ) ^{2}}{49} + \frac{( y ) ^{2}}{36} = 1

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

What is the eccentricity ((x-1)^2)/2+(y^2)/1 =1 ?
The eccentricity ((x-1)^2)/2+(y^2)/1 =1 is 1/(sqrt(2))