What is the eccentricity ((x+5)^2)/9+(y-1)^2=1 ?

The eccentricity ((x+5)^2)/9+(y-1)^2=1 is (2sqrt(2))/3

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eccentricity ((x+5)^2)/9+(y-1)^2=1

eccentricity

\frac{2 2}{3}

Decimal

0.94280 \dots

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1 :

Ellipse with center

(h, k) = (- 5, 1), a = 3, b = 1

= \frac{3 ^{2} - 1 ^{2}}{3}

\frac{3 ^{2} - 1 ^{2}}{3} = \frac{2 2}{3}

= \frac{2 2}{3}

What is the eccentricity ((x+5)^2)/9+(y-1)^2=1 ?
The eccentricity ((x+5)^2)/9+(y-1)^2=1 is (2sqrt(2))/3