What is the axis (x^2)/(25)+(y^2)/(36)=1 ?

The axis (x^2)/(25)+(y^2)/(36)=1 is semi-major axis b=6, semi-minor axis a=5

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axis (x^2)/(25)+(y^2)/(36)=1

axis

semi - major axis b = 6, semi - minor axis a = 5

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = 5

What is the axis (x^2)/(25)+(y^2)/(36)=1 ?
The axis (x^2)/(25)+(y^2)/(36)=1 is semi-major axis b=6, semi-minor axis a=5