What is the axis (x^2}{16}+\frac{y^2)/4 =1 ?

The axis (x^2}{16}+\frac{y^2)/4 =1 is semi-major axis a=4, semi-minor axis b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

axis (x^2}{16}+\frac{y^2)/4 =1

axis

semi - major axis a = 4, semi - minor axis b = 2

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 2

What is the axis (x^2}{16}+\frac{y^2)/4 =1 ?
The axis (x^2}{16}+\frac{y^2)/4 =1 is semi-major axis a=4, semi-minor axis b=2