What is the axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 ?

The axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 is semi-major axis a=7, semi-minor axis b=3

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axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1

axis

semi - major axis a = 7, semi - minor axis b = 3

Solution steps

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 8 ) ^{2}}{7 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (8, - 5), a = 7, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (8, - 5), a = 7, b = 3

What is the axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 ?
The axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 is semi-major axis a=7, semi-minor axis b=3