What is the axis (x^2)/(81)+(y^2)/(16)=1 ?

The axis (x^2)/(81)+(y^2)/(16)=1 is semi-major axis a=9, semi-minor axis b=4

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axis (x^2)/(81)+(y^2)/(16)=1

axis

\frac{x ^{2}}{81} + \frac{y ^{2}}{16} = 1

semi - major axis a = 9, semi - minor axis b = 4

Solution steps

\frac{x ^{2}}{81} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{81} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{9 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 9, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 9, b = 4

\frac{( x - 2 ) ^{2}}{64} + \frac{( y + 4 ) ^{2}}{16} = 1

9 x^{2} + 16 y^{2} - 54 x + 64 y + 1 = 0

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{16} = 1

\frac{( y + 4 ) ^{2}}{9} + \frac{( x - 9 ) ^{2}}{25} = 1

25 x^{2} + 16 y^{2} = 400

What is the axis (x^2)/(81)+(y^2)/(16)=1 ?
The axis (x^2)/(81)+(y^2)/(16)=1 is semi-major axis a=9, semi-minor axis b=4