What is the axis ((x-3)^2)/(49)+((y+6)^2)/(100)=1 ?

The axis ((x-3)^2)/(49)+((y+6)^2)/(100)=1 is semi-major axis b=10, semi-minor axis a=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis ((x-3)^2)/(49)+((y+6)^2)/(100)=1

axis

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 6 ) ^{2}}{100} = 1

semi - major axis b = 10, semi - minor axis a = 7

Solution steps

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 6 ) ^{2}}{100} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 6 ) ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - 3 ) ^{2}}{7 ^{2}} + \frac{( y - ( - 6 ) ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (3, - 6), a = 7, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (3, - 6), b = 10, a = 7

2 x^{2} + 7 y^{2} = 14

5 x^{2} + 2 y^{2} = 10

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

2 x^{2} + y^{2} = 50

4 x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

What is the axis ((x-3)^2)/(49)+((y+6)^2)/(100)=1 ?
The axis ((x-3)^2)/(49)+((y+6)^2)/(100)=1 is semi-major axis b=10, semi-minor axis a=7