What is the axis 4x^2+49y^2=196 ?

The axis 4x^2+49y^2=196 is semi-major axis a=7, semi-minor axis b=2

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axis 4x^2+49y^2=196

axis

semi - major axis a = 7, semi - minor axis b = 2

Solution steps

4 x^{2} + 49 y^{2} = 196

Rewrite

4 x^{2} + 49 y^{2} = 196

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 2

What is the axis 4x^2+49y^2=196 ?
The axis 4x^2+49y^2=196 is semi-major axis a=7, semi-minor axis b=2