What is the axis 49x^2+64y^2=25 ?

The axis 49x^2+64y^2=25 is semi-major axis a= 5/7 , semi-minor axis b= 5/8

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axis 49x^2+64y^2=25

axis

semi - major axis a = \frac{5}{7}, semi - minor axis b = \frac{5}{8}

Solution steps

49 x^{2} + 64 y^{2} = 25

Rewrite

49 x^{2} + 64 y^{2} = 25

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{5}{7} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{5}{8} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{5}{7}, b = \frac{5}{8}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{5}{7}, b = \frac{5}{8}

What is the axis 49x^2+64y^2=25 ?
The axis 49x^2+64y^2=25 is semi-major axis a= 5/7 , semi-minor axis b= 5/8