What is the axis ((x+6)^2}{18}+\frac{(y+3)^2)/9 =1 ?

The axis ((x+6)^2}{18}+\frac{(y+3)^2)/9 =1 is semi-major axis a=3sqrt(2), semi-minor axis b=3

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axis ((x+6)^2}{18}+\frac{(y+3)^2)/9 =1

axis

semi - major axis a = 32, semi - minor axis b = 3

Solution steps

\frac{( x + 6 ) ^{2}}{18} + \frac{( y + 3 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 6 ) ^{2}}{18} + \frac{( y + 3 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 6 ) ) ^{2}}{( 3 2 ) ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 6, - 3), a = 32, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 6, - 3), a = 32, b = 3

What is the axis ((x+6)^2}{18}+\frac{(y+3)^2)/9 =1 ?
The axis ((x+6)^2}{18}+\frac{(y+3)^2)/9 =1 is semi-major axis a=3sqrt(2), semi-minor axis b=3