What is the axis (x^2)/(16)+y^2=1 ?

The axis (x^2)/(16)+y^2=1 is semi-major axis a=4, semi-minor axis b=1

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axis (x^2)/(16)+y^2=1

axis

\frac{x ^{2}}{16} + y^{2} = 1

semi - major axis a = 4, semi - minor axis b = 1

Solution steps

\frac{x ^{2}}{16} + y^{2} = 1

Rewrite

\frac{x ^{2}}{16} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 1

3 x^{2} + 7 y^{2} - 12 x - 28 y + 19 = 0

x^{2} + y^{2} - 6 y = 0

\frac{x ^{2}}{20} + \frac{y ^{2}}{4} = 1

25 x^{2} + 4 y^{2} + 50 x - 16 y - 59 = 0

9 x^{2} + 4 y^{2} + 54 x - 8 y + 49 = 0

What is the axis (x^2)/(16)+y^2=1 ?
The axis (x^2)/(16)+y^2=1 is semi-major axis a=4, semi-minor axis b=1