What is the axis ((x+1)^2)/(64)+((y-1)^2)/(100)=1 ?

The axis ((x+1)^2)/(64)+((y-1)^2)/(100)=1 is semi-major axis b=10, semi-minor axis a=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

axis ((x+1)^2)/(64)+((y-1)^2)/(100)=1

axis

semi - major axis b = 10, semi - minor axis a = 8

Solution steps

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{8 ^{2}} + \frac{( y - 1 ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 1), a = 8, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 1), b = 10, a = 8

What is the axis ((x+1)^2)/(64)+((y-1)^2)/(100)=1 ?
The axis ((x+1)^2)/(64)+((y-1)^2)/(100)=1 is semi-major axis b=10, semi-minor axis a=8