What is the axis (x^2)/(49)+(y^2)/(169)=1 ?

The axis (x^2)/(49)+(y^2)/(169)=1 is semi-major axis b=13, semi-minor axis a=7

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axis (x^2)/(49)+(y^2)/(169)=1

axis

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

semi - major axis b = 13, semi - minor axis a = 7

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{1 3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 13

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 13, a = 7

5 x^{2} + 7 y^{2} = 35

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

(\frac{x - 3}{9})^{2} + (\frac{y + 1}{4})^{2} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

What is the axis (x^2)/(49)+(y^2)/(169)=1 ?
The axis (x^2)/(49)+(y^2)/(169)=1 is semi-major axis b=13, semi-minor axis a=7