What is the axis ((x-12)^2)/(100)+((y+7)^2)/(36)=1 ?

The axis ((x-12)^2)/(100)+((y+7)^2)/(36)=1 is semi-major axis a=10, semi-minor axis b=6

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axis ((x-12)^2)/(100)+((y+7)^2)/(36)=1

axis

\frac{( x - 12 ) ^{2}}{100} + \frac{( y + 7 ) ^{2}}{36} = 1

semi - major axis a = 10, semi - minor axis b = 6

Solution steps

\frac{( x - 12 ) ^{2}}{100} + \frac{( y + 7 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 12 ) ^{2}}{100} + \frac{( y + 7 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 12 ) ^{2}}{1 0 ^{2}} + \frac{( y - ( - 7 ) ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (12, - 7), a = 10, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (12, - 7), a = 10, b = 6

\frac{( y + 4 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

25 y^{2} - 16 x^{2} - 400 = 0

2 x^{2} - 2 y^{2} - 20 x + 16 y + 16 = 0

y^{2} - x^{2} + 1 = 50

x^{2} - y^{2} = 4 x

What is the axis ((x-12)^2)/(100)+((y+7)^2)/(36)=1 ?
The axis ((x-12)^2)/(100)+((y+7)^2)/(36)=1 is semi-major axis a=10, semi-minor axis b=6