What is -3x^2+2y^2+6x-7y=7 ?

The solution to -3x^2+2y^2+6x-7y=7 is Hyperbola with (h,k)=(1, 7/4),a= 9/4 ,b=(3sqrt(3))/(2sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-3x^2+2y^2+6x-7y=7

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

(h, k) = (1, \frac{7}{4}), a = \frac{9}{4}, b = \frac{3 3}{2 2}

Solution steps

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

Rewrite

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

in the form of a standard hyperbola equation

\frac{( y - \frac{7}{4} ) ^{2}}{( \frac{9}{4} ) ^{2}} - \frac{( x - 1 ) ^{2}}{( \frac{3 3}{2 2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, \frac{7}{4}), a = \frac{9}{4}, b = \frac{3 3}{2 2}

16 x^{2} - 9 y^{2} + 32 x + 72 y - 704 = 0

16 x^{2} - 25 y^{2} = 400

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

\frac{x ^{2}}{144} - \frac{y ^{2}}{81} = 1

y^{2} = x^{2} + 1

What is -3x^2+2y^2+6x-7y=7 ?
The solution to -3x^2+2y^2+6x-7y=7 is Hyperbola with (h,k)=(1, 7/4),a= 9/4 ,b=(3sqrt(3))/(2sqrt(2))