What is -3x^2+2y^2+6x-7y=7 ?

The solution to -3x^2+2y^2+6x-7y=7 is Hyperbola with (h,k)=(1, 7/4),a= 9/4 ,b=(3sqrt(3))/(2sqrt(2))

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-3x^2+2y^2+6x-7y=7

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

(h, k) = (1, \frac{7}{4}), a = \frac{9}{4}, b = \frac{3 3}{2 2}

Solution steps

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

Rewrite

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

in the form of a standard hyperbola equation

\frac{( y - \frac{7}{4} ) ^{2}}{( \frac{9}{4} ) ^{2}} - \frac{( x - 1 ) ^{2}}{( \frac{3 3}{2 2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, \frac{7}{4}), a = \frac{9}{4}, b = \frac{3 3}{2 2}

What is -3x^2+2y^2+6x-7y=7 ?
The solution to -3x^2+2y^2+6x-7y=7 is Hyperbola with (h,k)=(1, 7/4),a= 9/4 ,b=(3sqrt(3))/(2sqrt(2))