What is (y+9)^2-2(x-4)=0 ?

The solution to (y+9)^2-2(x-4)=0 is Parabola with (h,k)=(4,-9),p= 1/2

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(y+9)^2-2(x-4)=0

(y + 9)^{2} - 2 (x - 4) = 0

(h, k) = (4, - 9), p = \frac{1}{2}

Solution steps

(y + 9)^{2} - 2 (x - 4) = 0

Rewrite

(y + 9)^{2} - 2 (x - 4) = 0

in the standard form:

4 \cdot \frac{1}{2} (x - 4) = (y - (- 9))^{2}

Therefore parabola properties are:

(h, k) = (4, - 9), p = \frac{1}{2}

x = y^{2} + 4 y + 3

x^{2} + 8 y - 16 = 0

x^{2} - 10 x + k (x) = 0

x^{2} + 2 x + m (x) + 1 = 0

x = \frac{y ^{2} + 6 y + 9}{2}

What is (y+9)^2-2(x-4)=0 ?
The solution to (y+9)^2-2(x-4)=0 is Parabola with (h,k)=(4,-9),p= 1/2