What is (x^2)/4-((y+3)^2)/9 =1 ?

The solution to (x^2)/4-((y+3)^2)/9 =1 is Hyperbola with (h,k)=(0,-3),a=2,b=3

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(x^2)/4-((y+3)^2)/9 =1

\frac{x ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

(h, k) = (0, - 3), a = 2, b = 3

Solution steps

\frac{x ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 3), a = 2, b = 3

x^{2} - y^{2} = 100

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{16} = 1

\frac{y ^{2}}{36} - \frac{x ^{2}}{4} = 1

25 x^{2} - 4 y^{2} = 100

9 x^{2} - y^{2} = 36

What is (x^2)/4-((y+3)^2)/9 =1 ?
The solution to (x^2)/4-((y+3)^2)/9 =1 is Hyperbola with (h,k)=(0,-3),a=2,b=3