What is ((x+2)^2)/(25)-((y-1)^2)/(144)=1 ?

The solution to ((x+2)^2)/(25)-((y-1)^2)/(144)=1 is Hyperbola with (h,k)=(-2,1),a=5,b=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x+2)^2)/(25)-((y-1)^2)/(144)=1

\frac{( x + 2 ) ^{2}}{25} - \frac{( y - 1 ) ^{2}}{144} = 1

(h, k) = (- 2, 1), a = 5, b = 12

Solution steps

\frac{( x + 2 ) ^{2}}{25} - \frac{( y - 1 ) ^{2}}{144} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{25} - \frac{( y - 1 ) ^{2}}{144} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{5 ^{2}} - \frac{( y - 1 ) ^{2}}{1 2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 1), a = 5, b = 12

9 x^{2} - 4 y^{2} + 18 x - 24 y + 9 = 0

x^{2} - y^{2} + 8 x - 2 y + 14 = 0

x^{2} - y^{2} = 5

y^{2} - x^{2} = 2

x^{2} - 4 y^{2} - 4 x + 8 y - 16 = 0

What is ((x+2)^2)/(25)-((y-1)^2)/(144)=1 ?
The solution to ((x+2)^2)/(25)-((y-1)^2)/(144)=1 is Hyperbola with (h,k)=(-2,1),a=5,b=12