What is ((x-5)^2)/1-((y-4)^2)/1 =1 ?

The solution to ((x-5)^2)/1-((y-4)^2)/1 =1 is Hyperbola with (h,k)=(5,4),a=1,b=1

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((x-5)^2)/1-((y-4)^2)/1 =1

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

(h, k) = (5, 4), a = 1, b = 1

Solution steps

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{1 ^{2}} - \frac{( y - 4 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 4), a = 1, b = 1

y^{2} - y - x^{2} = 0

\frac{( x - 7 ) ^{2}}{64} - \frac{( y - 6 ) ^{2}}{36} = 1

\frac{y ^{2}}{144} - \frac{x ^{2}}{25} = 1

25 y^{2} - x^{2} = 100

p^{2} + p = q^{2}

What is ((x-5)^2)/1-((y-4)^2)/1 =1 ?
The solution to ((x-5)^2)/1-((y-4)^2)/1 =1 is Hyperbola with (h,k)=(5,4),a=1,b=1