What is 4y^2-x^2-40y+8x+80=0 ?

The solution to 4y^2-x^2-40y+8x+80=0 is Hyperbola with (h,k)=(4,5),a=1,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4y^2-x^2-40y+8x+80=0

4 y^{2} - x^{2} - 40 y + 8 x + 80 = 0

(h, k) = (4, 5), a = 1, b = 2

Solution steps

4 y^{2} - x^{2} - 40 y + 8 x + 80 = 0

Rewrite

4 y^{2} - x^{2} - 40 y + 8 x + 80 = 0

in the form of a standard hyperbola equation

\frac{( y - 5 ) ^{2}}{1 ^{2}} - \frac{( x - 4 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 5), a = 1, b = 2

x^{2} - y^{2} = x

3 x^{2} - 6 y^{2} - 36 = 0

(x - 5)^{2} - (y + 1)^{2} = 2

9 y^{2} - 25 x^{2} - 100 x - 108 y - 1 = 0

\frac{x ^{2}}{6} - \frac{y ^{2}}{25} = 1

What is 4y^2-x^2-40y+8x+80=0 ?
The solution to 4y^2-x^2-40y+8x+80=0 is Hyperbola with (h,k)=(4,5),a=1,b=2