What is -(x^2}{16}+\frac{y^2)/9 =1 ?

The solution to -(x^2}{16}+\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=3,b=4

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-(x^2}{16}+\frac{y^2)/9 =1

- \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 3, b = 4

Solution steps

- \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

Rewrite

- \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{3 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 4

y^{2} - \frac{x ^{2}}{4} = 1

x^{2} - y^{2} - 4 x - 2 y - 1 = 0

x^{2} - y^{2} + 6 x - 9 y + 81 = 0

(x - 1)^{2} - \frac{( y - 2 ) ^{2}}{3} = 1

x^{2} - 4 y^{2} = 9

What is -(x^2}{16}+\frac{y^2)/9 =1 ?
The solution to -(x^2}{16}+\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=3,b=4