What is y^1=8y-64x^2+6 ?

The solution to y^1=8y-64x^2+6 is Parabola with (h,k)=(0,-6/7),p= 7/256

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y^1=8y-64x^2+6

y^{1} = 8 y - 64 x^{2} + 6

(h, k) = (0, - \frac{6}{7}), p = \frac{7}{256}

Solution steps

y^{1} = 8 y - 64 x^{2} + 6

Rewrite

y^{1} = 8 y - 64 x^{2} + 6

in the standard form:

4 \cdot \frac{7}{256} (y - (- \frac{6}{7})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{6}{7}), p = \frac{7}{256}

(y - 6)^{2} = 32 (x + 1)

y^{2} - 4 y - 8 x + 44 = 0

y^{2} = - (x + 3)

5 x + y^{2} = 25

x^{2} + 3 y = 2

What is y^1=8y-64x^2+6 ?
The solution to y^1=8y-64x^2+6 is Parabola with (h,k)=(0,-6/7),p= 7/256