What is (x^2)/(16+(y-4)^2)=1 ?

The solution to (x^2)/(16+(y-4)^2)=1 is Hyperbola with (h,k)=(0,4),a=4,b=4

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(x^2)/(16+(y-4)^2)=1

\frac{x ^{2}}{16 + ( y - 4 ) ^{2}} = 1

(h, k) = (0, 4), a = 4, b = 4

Solution steps

\frac{x ^{2}}{16 + ( y - 4 ) ^{2}} = 1

Rewrite

\frac{x ^{2}}{16 + ( y - 4 ) ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 4 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 4), a = 4, b = 4

- \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

16 x^{2} - 9 y^{2} - 64 x + 54 y - 161 = 0

3 x^{2} - 2 y^{2} + 6 x - 8 y - 17 = 0

x^{2} = y^{2} + 1

4 x^{2} - 3 y^{2} = 11

What is (x^2)/(16+(y-4)^2)=1 ?
The solution to (x^2)/(16+(y-4)^2)=1 is Hyperbola with (h,k)=(0,4),a=4,b=4