What is 1/2 (y+4)=(x-7)^2 ?

The solution to 1/2 (y+4)=(x-7)^2 is Parabola with (h,k)=(7,-4),p= 1/8

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1/2 (y+4)=(x-7)^2

\frac{1}{2} (y + 4) = (x - 7)^{2}

(h, k) = (7, - 4), p = \frac{1}{8}

Solution steps

\frac{1}{2} (y + 4) = (x - 7)^{2}

Rewrite

\frac{1}{2} (y + 4) = (x - 7)^{2}

in the standard form:

4 \cdot \frac{1}{8} (y - (- 4)) = (x - 7)^{2}

Therefore parabola properties are:

(h, k) = (7, - 4), p = \frac{1}{8}

(x - 2)^{2} = - 20 (y - 3)

y^{2} - 4 y - 2 x + 14 = 0

(x - 3)^{2} = 16 y

x^{2} - 20 x + (10 p (x) + 10) = 0

4 t = 1 + 15 r^{2}

What is 1/2 (y+4)=(x-7)^2 ?
The solution to 1/2 (y+4)=(x-7)^2 is Parabola with (h,k)=(7,-4),p= 1/8