What is (x^2)/4-((y-6)^2)/(140)=1 ?

The solution to (x^2)/4-((y-6)^2)/(140)=1 is Hyperbola with (h,k)=(0,6),a=2,b=2sqrt(35)

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(x^2)/4-((y-6)^2)/(140)=1

\frac{x ^{2}}{4} - \frac{( y - 6 ) ^{2}}{140} = 1

(h, k) = (0, 6), a = 2, b = 235

Solution steps

\frac{x ^{2}}{4} - \frac{( y - 6 ) ^{2}}{140} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{( y - 6 ) ^{2}}{140} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 6 ) ^{2}}{( 2 35 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 6), a = 2, b = 235

\frac{y ^{2}}{49} - \frac{x ^{2}}{36} = 1

9 x^{2} - 36 x - 16 y^{2} - 32 y = 124

4 x^{2} - y^{2} - 36 = 0

\frac{x ^{2}}{3 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

5 x^{2} - 4 y^{2} - 40 x + 24 y + 24 = 0

What is (x^2)/4-((y-6)^2)/(140)=1 ?
The solution to (x^2)/4-((y-6)^2)/(140)=1 is Hyperbola with (h,k)=(0,6),a=2,b=2sqrt(35)