What is ((y+3)^2)/9-(x^2)/(16)=1 ?

The solution to ((y+3)^2)/9-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,-3),a=3,b=4

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((y+3)^2)/9-(x^2)/(16)=1

\frac{( y + 3 ) ^{2}}{9} - \frac{x ^{2}}{16} = 1

(h, k) = (0, - 3), a = 3, b = 4

Solution steps

\frac{( y + 3 ) ^{2}}{9} - \frac{x ^{2}}{16} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{9} - \frac{x ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{3 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 3), a = 3, b = 4

x^{2} - 6 = \frac{y ^{2}}{3}

12 (y - 5)^{2} - 30 (x + 2)^{2} = 360

3 x^{2} - y^{2} + 30 x + 78 = 0

9 x^{2} - y^{2} - 72 x + 8 y + 119 = 0

9 x^{2} - 4 y^{2} + 18 x - 27 = 0

What is ((y+3)^2)/9-(x^2)/(16)=1 ?
The solution to ((y+3)^2)/9-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,-3),a=3,b=4