What is ((y+1)^2)/(sqrt(5)^2)-((x-1)^2)/(1^2)=1 ?

The solution to ((y+1)^2)/(sqrt(5)^2)-((x-1)^2)/(1^2)=1 is Hyperbola with (h,k)=(1,-1),a=sqrt(5),b=1

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((y+1)^2)/(sqrt(5)^2)-((x-1)^2)/(1^2)=1

\frac{( y + 1 ) ^{2}}{5 ^{2}} - \frac{( x - 1 ) ^{2}}{1 ^{2}} = 1

(h, k) = (1, - 1), a = 5, b = 1

Solution steps

\frac{( y + 1 ) ^{2}}{( 5 ) ^{2}} - \frac{( x - 1 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 1), a = 5, b = 1

\frac{y ^{2}}{15} - \frac{x ^{2}}{1} = 1

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

x^{2} - 2 y^{2} - 2 x - 8 y - 27 = 0

x, 0 = x^{2} + 2 x - 2 m (x)^{2}

\frac{( x - 1 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

What is ((y+1)^2)/(sqrt(5)^2)-((x-1)^2)/(1^2)=1 ?
The solution to ((y+1)^2)/(sqrt(5)^2)-((x-1)^2)/(1^2)=1 is Hyperbola with (h,k)=(1,-1),a=sqrt(5),b=1