What is ((x-5)^2)/(25)-((y-5)^2)/(16)=1 ?

The solution to ((x-5)^2)/(25)-((y-5)^2)/(16)=1 is Hyperbola with (h,k)=(5,5),a=5,b=4

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((x-5)^2)/(25)-((y-5)^2)/(16)=1

\frac{( x - 5 ) ^{2}}{25} - \frac{( y - 5 ) ^{2}}{16} = 1

(h, k) = (5, 5), a = 5, b = 4

Solution steps

\frac{( x - 5 ) ^{2}}{25} - \frac{( y - 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{25} - \frac{( y - 5 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{5 ^{2}} - \frac{( y - 5 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 5), a = 5, b = 4

2 x^{2} - 2 y^{2} - 2 x + 4 y = \frac{1}{2}

x^{2} - x - 4 y^{2} + 24 y - 35 = 0

x^{2} - y^{2} + 16 = 0

y^{2} = x^{2} + 12

x^{2} - 2 x = y^{2}

What is ((x-5)^2)/(25)-((y-5)^2)/(16)=1 ?
The solution to ((x-5)^2)/(25)-((y-5)^2)/(16)=1 is Hyperbola with (h,k)=(5,5),a=5,b=4