What is ((x)^2)/4-((y+1)^2)/(16)=1 ?

The solution to ((x)^2)/4-((y+1)^2)/(16)=1 is Hyperbola with (h,k)=(0,-1),a=2,b=4

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((x)^2)/4-((y+1)^2)/(16)=1

\frac{( x ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

(h, k) = (0, - 1), a = 2, b = 4

Solution steps

\frac{x ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 1), a = 2, b = 4

x^{2} - y^{2} = 11

4 y^{2} - x^{2} = 2500

4 x^{2} - 8 x - 9 y^{2} - 72 y + 112 = 0

y^{2} = 4 0^{2} + x^{2}

x^{2} - 3 y^{2} - 8 x + 18 y - 14 = 0

What is ((x)^2)/4-((y+1)^2)/(16)=1 ?
The solution to ((x)^2)/4-((y+1)^2)/(16)=1 is Hyperbola with (h,k)=(0,-1),a=2,b=4