What is ((x-8)^2}{64}-\frac{(y-9)^2)/4 =1 ?

The solution to ((x-8)^2}{64}-\frac{(y-9)^2)/4 =1 is Hyperbola with (h,k)=(8,9),a=8,b=2

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((x-8)^2}{64}-\frac{(y-9)^2)/4 =1

\frac{( x - 8 ) ^{2}}{64} - \frac{( y - 9 ) ^{2}}{4} = 1

(h, k) = (8, 9), a = 8, b = 2

Solution steps

\frac{( x - 8 ) ^{2}}{64} - \frac{( y - 9 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 8 ) ^{2}}{64} - \frac{( y - 9 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 8 ) ^{2}}{8 ^{2}} - \frac{( y - 9 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (8, 9), a = 8, b = 2

a^{2} - b^{2} = 4

9 x^{2} - 25 y^{2} = 1

(x + 3)^{2} - (y + 2)^{2} = 3

9 x^{2} - 4 y^{2} - 54 x + 17 y - 20 = 0

\frac{x ^{2}}{729} - \frac{y ^{2}}{484} = 1

What is ((x-8)^2}{64}-\frac{(y-9)^2)/4 =1 ?
The solution to ((x-8)^2}{64}-\frac{(y-9)^2)/4 =1 is Hyperbola with (h,k)=(8,9),a=8,b=2